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Multiplying Numbers Ending in Zeros

RuleMultipl y the two numbers as if they did not end in zeros. Then affix an amount of zeros equal to the sum of all the zeros ignored in the multlphcatlon.

To provide a simple example:

Multiply these two numbers:

23,000*3,000

Applying the above rule:

{23,000*3,000}={23*3} {000 000}={69,000,000}

Multiply the numbers without zeros.

{23*3}={69}

Add the zeros : {000 000}

It will then result to:

{23,000*3,000}={69,000,000}

Posted in Multiplication.


Adding a Series of Numbers with a Common Ratio

RuleMultiply the ratio by itself as many times as there are number of items in the series. Subtract 1 from the product and multiply by the first number in the series. Divide the result by one less than the ratio.

In symbol notation:

x={({y^n}-1)*a}/{(y-1)}

where:

x = the sum of all numbers in the sries

y = the common ratio of the numbers

a = the first number in the series

n = the number of items in the series

This rule is best applied when the ratio and the number of items in the series are small else the purpose of the short cut will be defeated.

Example:

Add the following numbers: 11, 22, 44, 88, 176, 352.

Solution:

y=2

n=6

a=11

x={({y^n}-1)*a}/{(y-1)}

x={({2^6}-1)*11}/{(2-1)}

x=693

The traditional way:

x=11+22+44+88+176+352=693

Posted in Addition.


Adding a Series of Numbers with a Common Difference

RuleAdd the smallest number to the largest number in the series, multiply the sum by the numbers of items in the series, then divide by 2.

x=(a+b)*y/2

where:

x – the sum of the numbers in the series

a – the smallest number in the series

b – the largest number in the series

y – the numbers items in the series

Example 1:

Find the sum of the numbers in the series 35, 39, 43, 47, 51

x=(35+51)*5/2

x=215

Posted in Addition.


Add Consecutive Even Numbers Starting from 2

To calculate the sum of all even numbers in a seires starting from 2, apply the this rule:

RuleMultiply the number of items in the series by the one more than number of items.

In symbol notation:

x=y*(y+1)

where:

x = the sum of all odd numbers in the series starting from 2

y = the number of items in the series

To calculate the number of items in a given series, divide the highest number in the series by 2.

Integrating this rule into the above rule.

x={N/2}*(N/2+1)

where N = highest number in the series.

To illustrate this rule, let us have some examples:

Example 1:

Calculate the sume of all odd number from 2 to 48.

Solution:

In this example, {N=48}{, }{y=48/2=24}

x=24*(24+1)

x=600

 

Example 2:

Calculate the sume of all odd number from 2 to 86.

Solution:

In this example, {N=86}{, }{y=86/2=43}

x=43*(43+1)

x=1,892

Try the following exercises:

  1. 2 to 100 – Answer: 2,550
  2. 2 to 124 – Answer: 3,906

Posted in Addition.




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